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(7x-4)(2x-19)=0
We multiply parentheses ..
(+14x^2-133x-8x+76)=0
We get rid of parentheses
14x^2-133x-8x+76=0
We add all the numbers together, and all the variables
14x^2-141x+76=0
a = 14; b = -141; c = +76;
Δ = b2-4ac
Δ = -1412-4·14·76
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15625}=125$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-141)-125}{2*14}=\frac{16}{28} =4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-141)+125}{2*14}=\frac{266}{28} =9+1/2 $
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