(7x-3)(x+2=)

Solution for (7x-3)(x+2=) equation:

(7x-3)(x+2=)

We move all terms to the left:

(7x-3)(x+2-())=0


We calculate terms in parentheses: +(7x-3)(x+2-()), so:

7x-3)(x+2-()

We add all the numbers together, and all the variables

7x-3)(x

Back to the equation:

+(7x-3)(x)


We multiply parentheses

7x^2-3x=0

a = 7; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·7·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*7}=\frac{6}{14}
=3/7
$