15x-10-12x=247+4x-228

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Solution for 15x-10-12x=247+4x-228 equation: 



15x-10-12x=247+4x-228

We move all terms to the left:

15x-10-12x-(247+4x-228)=0

We add all the numbers together, and all the variables

15x-12x-(4x+19)-10=0

We add all the numbers together, and all the variables

3x-(4x+19)-10=0

We get rid of parentheses

3x-4x-19-10=0

We add all the numbers together, and all the variables

-1x-29=0

We move all terms containing x to the left, all other terms to the right

-x=29

x=29/-1

x=-29

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