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3(x-4)=x(x+1)
We move all terms to the left:
3(x-4)-(x(x+1))=0
We multiply parentheses
3x-(x(x+1))-12=0
We calculate terms in parentheses: -(x(x+1)), so:We get rid of parentheses
x(x+1)
We multiply parentheses
x^2+x
Back to the equation:
-(x^2+x)
-x^2+3x-x-12=0
We add all the numbers together, and all the variables
-1x^2+2x-12=0
a = -1; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-1)·(-12)
Δ = -44
Delta is less than zero, so there is no solution for the equation
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