(7x-3)(4x-8)=0

Solution for (7x-3)(4x-8)=0 equation:

(7x-3)(4x-8)=0

We multiply parentheses ..

(+28x^2-56x-12x+24)=0

We get rid of parentheses

28x^2-56x-12x+24=0

We add all the numbers together, and all the variables

28x^2-68x+24=0

a = 28; b = -68; c = +24;
Δ = b2-4ac
Δ = -682-4·28·24
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-44}{2*28}=\frac{24}{56}
=3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+44}{2*28}=\frac{112}{56}
=2
$