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-1/2-(1/2x+4)+12=17x-6(3x+5/6)
We move all terms to the left:
-1/2-(1/2x+4)+12-(17x-6(3x+5/6))=0
Domain of the equation: 2x+4)!=0We add all the numbers together, and all the variables
x∈R
-(1/2x+4)-(17x-6(+3x+5/6))+12-1/2=0
We get rid of parentheses
-1/2x-(17x-6(+3x+5/6))-4+12-1/2=0
We calculate fractions
()/24x^2+(-(17x-6(+3x+5*2x*2)/24x^2+()/24x^2-4+12=0
We can not solve this equation
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