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(7x-3)(2x-6)=180
We move all terms to the left:
(7x-3)(2x-6)-(180)=0
We multiply parentheses ..
(+14x^2-42x-6x+18)-180=0
We get rid of parentheses
14x^2-42x-6x+18-180=0
We add all the numbers together, and all the variables
14x^2-48x-162=0
a = 14; b = -48; c = -162;
Δ = b2-4ac
Δ = -482-4·14·(-162)
Δ = 11376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11376}=\sqrt{144*79}=\sqrt{144}*\sqrt{79}=12\sqrt{79}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-12\sqrt{79}}{2*14}=\frac{48-12\sqrt{79}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+12\sqrt{79}}{2*14}=\frac{48+12\sqrt{79}}{28} $
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