3(v-1)=2v+3-3(-5v-4)

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Solution for 3(v-1)=2v+3-3(-5v-4) equation: 



3(v-1)=2v+3-3(-5v-4)

We move all terms to the left:

3(v-1)-(2v+3-3(-5v-4))=0

We multiply parentheses

3v-(2v+3-3(-5v-4))-3=0



We calculate terms in parentheses: -(2v+3-3(-5v-4)), so:

2v+3-3(-5v-4)

determiningTheFunctionDomain
2v-3(-5v-4)+3

We multiply parentheses

2v+15v+12+3

We add all the numbers together, and all the variables

17v+15

Back to the equation:

-(17v+15)



We get rid of parentheses

3v-17v-15-3=0

We add all the numbers together, and all the variables

-14v-18=0

We move all terms containing v to the left, all other terms to the right

-14v=18

v=18/-14

v=-1+2/7

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