(2x/5)=(7/35)

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Solution for (2x/5)=(7/35) equation:



(2x/5)=(7/35)
We move all terms to the left:
(2x/5)-((7/35))=0
We add all the numbers together, and all the variables
(+2x/5)-((+7/35))=0
We get rid of parentheses
2x/5-((+7/35))=0
We calculate fractions
70x^2/()+()/()=0
We add all the numbers together, and all the variables
70x^2/()+1=0
We multiply all the terms by the denominator
70x^2+1*()=0
We add all the numbers together, and all the variables
70x^2=0
a = 70; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·70·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{140}=0$

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