(7x-20)=(2x+11)

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Solution for (7x-20)=(2x+11) equation: 



(7x-20)=(2x+11)

We move all terms to the left:

(7x-20)-((2x+11))=0

We get rid of parentheses

7x-((2x+11))-20=0



We calculate terms in parentheses: -((2x+11)), so:

(2x+11)

We get rid of parentheses

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

7x-2x-11-20=0

We add all the numbers together, and all the variables

5x-31=0

We move all terms containing x to the left, all other terms to the right

5x=31

x=31/5

x=6+1/5

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