10(1/5x+2)+3(2x+1)=103

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Solution for 10(1/5x+2)+3(2x+1)=103 equation: 



10(1/5x+2)+3(2x+1)=103

We move all terms to the left:

10(1/5x+2)+3(2x+1)-(103)=0



Domain of the equation: 5x+2)!=0

x∈R



We multiply parentheses

10x+6x+20+3-103=0

We add all the numbers together, and all the variables

16x-80=0

We move all terms containing x to the left, all other terms to the right

16x=80

x=80/16

x=5

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