(7x-2)/7=(5x-3)/4

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Solution for (7x-2)/7=(5x-3)/4 equation: 



(7x-2)/7=(5x-3)/4

We move all terms to the left:

(7x-2)/7-((5x-3)/4)=0

We calculate fractions


7x/()+(-((5x-3)*7)/()=0



We calculate terms in parentheses: +(-((5x-3)*7)/(), so:

-((5x-3)*7)/(

We multiply all the terms by the denominator


-((5x-3)*7)



We calculate terms in parentheses: -((5x-3)*7), so:

(5x-3)*7

We multiply parentheses

35x-21

Back to the equation:

-(35x-21)



We get rid of parentheses

-35x+21

Back to the equation:

+(-35x+21)



We get rid of parentheses

7x/()-35x+21=0

We multiply all the terms by the denominator


7x-35x*()+21*()=0

We add all the numbers together, and all the variables

7x-35x*()=0

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