(7x-1)/5=3(5+2x)/3

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Solution for (7x-1)/5=3(5+2x)/3 equation: 



(7x-1)/5=3(5+2x)/3

We move all terms to the left:

(7x-1)/5-(3(5+2x)/3)=0

We add all the numbers together, and all the variables

(7x-1)/5-(3(2x+5)/3)=0

We calculate fractions


7x/()+(-(3(2x+5)*5)/()=0



We calculate terms in parentheses: +(-(3(2x+5)*5)/(), so:

-(3(2x+5)*5)/(

We multiply all the terms by the denominator


-(3(2x+5)*5)



We calculate terms in parentheses: -(3(2x+5)*5), so:

3(2x+5)*5

We multiply parentheses

30x+75

Back to the equation:

-(30x+75)



We get rid of parentheses

-30x-75

Back to the equation:

+(-30x-75)



We get rid of parentheses

7x/()-30x-75=0

We multiply all the terms by the denominator


7x-30x*()-75*()=0

We add all the numbers together, and all the variables

7x-30x*()=0

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