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(12-0.5x)(5x+20)=0
We add all the numbers together, and all the variables
(-0.5x+12)(5x+20)=0
We multiply parentheses ..
(+0x^2+0x+60x+240)=0
We get rid of parentheses
0x^2+0x+60x+240=0
We add all the numbers together, and all the variables
x^2+61x+240=0
a = 1; b = 61; c = +240;
Δ = b2-4ac
Δ = 612-4·1·240
Δ = 2761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{2761}}{2*1}=\frac{-61-\sqrt{2761}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{2761}}{2*1}=\frac{-61+\sqrt{2761}}{2} $
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