If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(11x+2)=11
We move all terms to the left:
x(11x+2)-(11)=0
We multiply parentheses
11x^2+2x-11=0
a = 11; b = 2; c = -11;
Δ = b2-4ac
Δ = 22-4·11·(-11)
Δ = 488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{488}=\sqrt{4*122}=\sqrt{4}*\sqrt{122}=2\sqrt{122}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{122}}{2*11}=\frac{-2-2\sqrt{122}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{122}}{2*11}=\frac{-2+2\sqrt{122}}{22} $
| 9x6=50 | | 4.9=35x | | 25-y=2y+13 | | 5y+16/3/2-5/6y=1/3 | | 10−2(a−1)=3+a | | u-7.87=9.26 | | x/15+9=3*2 | | -2x+25x+17=-35 | | q/5-25=-22 | | x+6-2x=2(x-3) | | -8(x+3)-6=-30 | | 7(-6x+6)=-252 | | 25-y=2y=+13 | | .4x-8=3x+2 | | (3y^2)^2÷(6y)^3=(y÷24) | | 35+4m=45 | | -6(4x+6)=-276 | | 6x-5(2+3)=55 | | 26s=7 | | (12-0.5x)(5x+20)=0 | | 6(s-82)=78 | | −4x+3=19+ | | -2x+8=-7x-17 | | 5h-7=5(h-2)=+3 | | 30x-6=180 | | -5/12x=15 | | 85+4x+1=22x-4 | | 5=2n-3= | | 10+x3/2+1/2=15 | | 7–2q=1 | | 2,000+100h=1,800+150h | | 2x=4+4x+5=13 |