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(7x-1)(9x+8)=0
We multiply parentheses ..
(+63x^2+56x-9x-8)=0
We get rid of parentheses
63x^2+56x-9x-8=0
We add all the numbers together, and all the variables
63x^2+47x-8=0
a = 63; b = 47; c = -8;
Δ = b2-4ac
Δ = 472-4·63·(-8)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-65}{2*63}=\frac{-112}{126} =-8/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+65}{2*63}=\frac{18}{126} =1/7 $
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