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(3+2)2z=3(z+2)
We move all terms to the left:
(3+2)2z-(3(z+2))=0
We add all the numbers together, and all the variables
52z-(3(z+2))=0
We calculate terms in parentheses: -(3(z+2)), so:We get rid of parentheses
3(z+2)
We multiply parentheses
3z+6
Back to the equation:
-(3z+6)
52z-3z-6=0
We add all the numbers together, and all the variables
49z-6=0
We move all terms containing z to the left, all other terms to the right
49z=6
z=6/49
z=6/49
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