(20y-11)+(4y+7)+(7y-7)=180

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Solution for (20y-11)+(4y+7)+(7y-7)=180 equation: 



(20y-11)+(4y+7)+(7y-7)=180

We move all terms to the left:

(20y-11)+(4y+7)+(7y-7)-(180)=0

We get rid of parentheses

20y+4y+7y-11+7-7-180=0

We add all the numbers together, and all the variables

31y-191=0

We move all terms containing y to the left, all other terms to the right

31y=191

y=191/31

y=6+5/31

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