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(7x+5)(2x+20)=21
We move all terms to the left:
(7x+5)(2x+20)-(21)=0
We multiply parentheses ..
(+14x^2+140x+10x+100)-21=0
We get rid of parentheses
14x^2+140x+10x+100-21=0
We add all the numbers together, and all the variables
14x^2+150x+79=0
a = 14; b = 150; c = +79;
Δ = b2-4ac
Δ = 1502-4·14·79
Δ = 18076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18076}=\sqrt{4*4519}=\sqrt{4}*\sqrt{4519}=2\sqrt{4519}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{4519}}{2*14}=\frac{-150-2\sqrt{4519}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{4519}}{2*14}=\frac{-150+2\sqrt{4519}}{28} $
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