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12y+2=6(2y+1)
We move all terms to the left:
12y+2-(6(2y+1))=0
We calculate terms in parentheses: -(6(2y+1)), so:We get rid of parentheses
6(2y+1)
We multiply parentheses
12y+6
Back to the equation:
-(12y+6)
12y-12y-6+2=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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