(11u)(3u-5)=0

Solution for (11u)(3u-5)=0 equation:

(11u)(3u-5)=0

We multiply parentheses

33u^2-55u=0

a = 33; b = -55; c = 0;
Δ = b2-4ac
Δ = -552-4·33·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-55}{2*33}=\frac{0}{66}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+55}{2*33}=\frac{110}{66}
=1+2/3
$