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(7q-46)=(3q+6)
We move all terms to the left:
(7q-46)-((3q+6))=0
We get rid of parentheses
7q-((3q+6))-46=0
We calculate terms in parentheses: -((3q+6)), so:We get rid of parentheses
(3q+6)
We get rid of parentheses
3q+6
Back to the equation:
-(3q+6)
7q-3q-6-46=0
We add all the numbers together, and all the variables
4q-52=0
We move all terms containing q to the left, all other terms to the right
4q=52
q=52/4
q=13
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