(7/2)-(m/9)=(1/18)

Solution for (7/2)-(m/9)=(1/18) equation:

(7/2)-(m/9)=(1/18)

We move all terms to the left:

(7/2)-(m/9)-((1/18))=0

We add all the numbers together, and all the variables

-(+m/9)+(+7/2)-((+1/18))=0

We get rid of parentheses

-m/9+7/2-((+1/18))=0

We calculate fractions


(-36m^2)/()+()/()+()/()=0

We add all the numbers together, and all the variables

(-36m^2)/()+2=0

We multiply all the terms by the denominator


(-36m^2)+2*()=0

We add all the numbers together, and all the variables

(-36m^2)=0

We get rid of parentheses

-36m^2=0

a = -36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-36)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-72}=0$