2(3-x)-4(5-2x)=16+4(6-2x)

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Solution for 2(3-x)-4(5-2x)=16+4(6-2x) equation: 



2(3-x)-4(5-2x)=16+4(6-2x)

We move all terms to the left:

2(3-x)-4(5-2x)-(16+4(6-2x))=0

We add all the numbers together, and all the variables

2(-1x+3)-4(-2x+5)-(16+4(-2x+6))=0

We multiply parentheses

-2x+8x-(16+4(-2x+6))+6-20=0



We calculate terms in parentheses: -(16+4(-2x+6)), so:

16+4(-2x+6)

determiningTheFunctionDomain
4(-2x+6)+16

We multiply parentheses

-8x+24+16

We add all the numbers together, and all the variables

-8x+40

Back to the equation:

-(-8x+40)



We add all the numbers together, and all the variables

6x-(-8x+40)-14=0

We get rid of parentheses

6x+8x-40-14=0

We add all the numbers together, and all the variables

14x-54=0

We move all terms containing x to the left, all other terms to the right

14x=54

x=54/14

x=3+6/7

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