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(7-2y/2)-(2/5)(2-y)=(5/4)
We move all terms to the left:
(7-2y/2)-(2/5)(2-y)-((5/4))=0
Domain of the equation: 5)(2-y)!=0We add all the numbers together, and all the variables
y∈R
(-2y/2+7)-(+2/5)(-1y+2)-((+5/4))=0
We get rid of parentheses
-2y/2-(+2/5)(-1y+2)+7-((+5/4))=0
We multiply parentheses ..
-(-2y^2+2/5*2)-2y/2+7-((+5/4))=0
We calculate fractions
We do not support eypression: y^3
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