1=-6(-x/2-5)-(x+3)

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Solution for 1=-6(-x/2-5)-(x+3) equation: 



1=-6(-x/2-5)-(x+3)

We move all terms to the left:

1-(-6(-x/2-5)-(x+3))=0



Domain of the equation: 2-5)-(x+3))!=0

We move all terms containing x to the left, all other terms to the right

-5)-(x+3))!=-2

x∈R



We multiply all the terms by the denominator


-(-6(-x+1*2-5)-(x+3))=0



We calculate terms in parentheses: -(-6(-x+1*2-5)-(x+3)), so:

-6(-x+1*2-5)-(x+3)

We add all the numbers together, and all the variables

-6(-1x-3)-(x+3)

We multiply parentheses

6x-(x+3)+18

We get rid of parentheses

6x-x-3+18

We add all the numbers together, and all the variables

5x+15

Back to the equation:

-(5x+15)



We get rid of parentheses

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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