4x/3-(x-1)/2=(11/4)

Solution for 4x/3-(x-1)/2=(11/4) equation:

4x/3-(x-1)/2=(11/4)

We move all terms to the left:

4x/3-(x-1)/2-((11/4))=0

We add all the numbers together, and all the variables

4x/3-(x-1)/2-((+11/4))=0

We calculate fractions


128x^2/()+(-x)/()+()/()=0

We add all the numbers together, and all the variables

128x^2/()+(-1x)/()+()/()=0

We add all the numbers together, and all the variables

128x^2/()+(-1x)/()+1=0

We multiply all the terms by the denominator


128x^2+(-1x)+1*()=0

We add all the numbers together, and all the variables

128x^2+(-1x)=0

We get rid of parentheses

128x^2-1x=0

a = 128; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·128·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*128}=\frac{0}{256}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*128}=\frac{2}{256}
=1/128
$