(6z-12=2z+60)

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Solution for (6z-12=2z+60) equation: 



(6z-12=2z+60)

We move all terms to the left:

(6z-12-(2z+60))=0



We calculate terms in parentheses: +(6z-12-(2z+60)), so:

6z-12-(2z+60)

determiningTheFunctionDomain
6z-(2z+60)-12

We get rid of parentheses

6z-2z-60-12

We add all the numbers together, and all the variables

4z-72

Back to the equation:

+(4z-72)



We get rid of parentheses

4z-72=0

We move all terms containing z to the left, all other terms to the right

4z=72

z=72/4

z=18

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