22=3(-7-9c)+27c

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Solution for 22=3(-7-9c)+27c equation: 



22=3(-7-9c)+27c

We move all terms to the left:

22-(3(-7-9c)+27c)=0

We add all the numbers together, and all the variables

-(3(-9c-7)+27c)+22=0



We calculate terms in parentheses: -(3(-9c-7)+27c), so:

3(-9c-7)+27c

We add all the numbers together, and all the variables

27c+3(-9c-7)

We multiply parentheses

27c-27c-21

We add all the numbers together, and all the variables

-21

Back to the equation:

-(-21)



We add all the numbers together, and all the variables

43!=0

There is no solution for this equation

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