32c+12=2c+3(4+10c)

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Solution for 32c+12=2c+3(4+10c) equation: 



32c+12=2c+3(4+10c)

We move all terms to the left:

32c+12-(2c+3(4+10c))=0

We add all the numbers together, and all the variables

32c-(2c+3(10c+4))+12=0



We calculate terms in parentheses: -(2c+3(10c+4)), so:

2c+3(10c+4)

We multiply parentheses

2c+30c+12

We add all the numbers together, and all the variables

32c+12

Back to the equation:

-(32c+12)



We get rid of parentheses

32c-32c-12+12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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