(6x-7)=(2x+12)+(x-1)

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Solution for (6x-7)=(2x+12)+(x-1) equation: 



(6x-7)=(2x+12)+(x-1)

We move all terms to the left:

(6x-7)-((2x+12)+(x-1))=0

We get rid of parentheses

6x-((2x+12)+(x-1))-7=0



We calculate terms in parentheses: -((2x+12)+(x-1)), so:

(2x+12)+(x-1)

We get rid of parentheses

2x+x+12-1

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

6x-3x-11-7=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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