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5x^2=103x+6
We move all terms to the left:
5x^2-(103x+6)=0
We get rid of parentheses
5x^2-103x-6=0
a = 5; b = -103; c = -6;
Δ = b2-4ac
Δ = -1032-4·5·(-6)
Δ = 10729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-\sqrt{10729}}{2*5}=\frac{103-\sqrt{10729}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+\sqrt{10729}}{2*5}=\frac{103+\sqrt{10729}}{10} $
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