-2/3(x-5)=3/2(x+1)

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Solution for -2/3(x-5)=3/2(x+1) equation: 



-2/3(x-5)=3/2(x+1)

We move all terms to the left:

-2/3(x-5)-(3/2(x+1))=0



Domain of the equation: 3(x-5)!=0

x∈R





Domain of the equation: 2(x+1))!=0

x∈R



We calculate fractions


(-4xx/(3(x-5)*2(x+1)))+(-9xx/(3(x-5)*2(x+1)))=0



We calculate terms in parentheses: +(-4xx/(3(x-5)*2(x+1))), so:

-4xx/(3(x-5)*2(x+1))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)





We calculate terms in parentheses: +(-9xx/(3(x-5)*2(x+1))), so:

-9xx/(3(x-5)*2(x+1))

We multiply all the terms by the denominator


-9xx

Back to the equation:

+(-9xx)



We get rid of parentheses

-4xx-9xx=0

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