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(6x-7)(2x+1)=0
We multiply parentheses ..
(+12x^2+6x-14x-7)=0
We get rid of parentheses
12x^2+6x-14x-7=0
We add all the numbers together, and all the variables
12x^2-8x-7=0
a = 12; b = -8; c = -7;
Δ = b2-4ac
Δ = -82-4·12·(-7)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-20}{2*12}=\frac{-12}{24} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+20}{2*12}=\frac{28}{24} =1+1/6 $
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