7(y-4)=5y-12

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Solution for 7(y-4)=5y-12 equation:



7(y-4)=5y-12
We move all terms to the left:
7(y-4)-(5y-12)=0
We multiply parentheses
7y-(5y-12)-28=0
We get rid of parentheses
7y-5y+12-28=0
We add all the numbers together, and all the variables
2y-16=0
We move all terms containing y to the left, all other terms to the right
2y=16
y=16/2
y=8

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