-5(2x-15)=2(x-2)-41

Solution for -5(2x-15)=2(x-2)-41 equation:

-5(2x-15)=2(x-2)-41

We move all terms to the left:

-5(2x-15)-(2(x-2)-41)=0

We multiply parentheses

-10x-(2(x-2)-41)+75=0


We calculate terms in parentheses: -(2(x-2)-41), so:

2(x-2)-41

We multiply parentheses

2x-4-41

We add all the numbers together, and all the variables

2x-45

Back to the equation:

-(2x-45)


We get rid of parentheses

-10x-2x+45+75=0

We add all the numbers together, and all the variables

-12x+120=0

We move all terms containing x to the left, all other terms to the right

-12x=-120

x=-120/-12

x=+10