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1/2(x-4)=16+5x
We move all terms to the left:
1/2(x-4)-(16+5x)=0
Domain of the equation: 2(x-4)!=0We add all the numbers together, and all the variables
x∈R
1/2(x-4)-(5x+16)=0
We get rid of parentheses
1/2(x-4)-5x-16=0
We multiply all the terms by the denominator
-5x*2(x-4)-16*2(x-4)+1=0
Wy multiply elements
-10x^2(x-32x(x+1=0
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