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(6x-42)=(x+28)
We move all terms to the left:
(6x-42)-((x+28))=0
We get rid of parentheses
6x-((x+28))-42=0
We calculate terms in parentheses: -((x+28)), so:We get rid of parentheses
(x+28)
We get rid of parentheses
x+28
Back to the equation:
-(x+28)
6x-x-28-42=0
We add all the numbers together, and all the variables
5x-70=0
We move all terms containing x to the left, all other terms to the right
5x=70
x=70/5
x=14
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