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(2x-3.6)(4-0.3x)=0
We add all the numbers together, and all the variables
(2x-3.6)(-0.3x+4)=0
We multiply parentheses ..
(+0x^2+8x-0x-14.4)=0
We get rid of parentheses
0x^2+8x-0x-14.4=0
We add all the numbers together, and all the variables
x^2+7x-14.4=0
a = 1; b = 7; c = -14.4;
Δ = b2-4ac
Δ = 72-4·1·(-14.4)
Δ = 106.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{106.6}}{2*1}=\frac{-7-\sqrt{106.6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{106.6}}{2*1}=\frac{-7+\sqrt{106.6}}{2} $
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