)16=4+2(m+1)

Solution for )16=4+2(m+1) equation:

)16=4+2(m+1)

We move all terms to the left:

)16-(4+2(m+1))=0

We add all the numbers together, and all the variables

-(4+2(m+1))=0


We calculate terms in parentheses: -(4+2(m+1)), so:

4+2(m+1)

determiningTheFunctionDomain
2(m+1)+4

We multiply parentheses

2m+2+4

We add all the numbers together, and all the variables

2m+6

Back to the equation:

-(2m+6)


We get rid of parentheses

-2m-6=0

We move all terms containing m to the left, all other terms to the right

-2m=6

m=6/-2

m=-3