(6x-3)/9=(4x-11)/3

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Solution for (6x-3)/9=(4x-11)/3 equation: 



(6x-3)/9=(4x-11)/3

We move all terms to the left:

(6x-3)/9-((4x-11)/3)=0

We calculate fractions


6x/()+(-((4x-11)*9)/()=0



We calculate terms in parentheses: +(-((4x-11)*9)/(), so:

-((4x-11)*9)/(

We multiply all the terms by the denominator


-((4x-11)*9)



We calculate terms in parentheses: -((4x-11)*9), so:

(4x-11)*9

We multiply parentheses

36x-99

Back to the equation:

-(36x-99)



We get rid of parentheses

-36x+99

Back to the equation:

+(-36x+99)



We get rid of parentheses

6x/()-36x+99=0

We multiply all the terms by the denominator


6x-36x*()+99*()=0

We add all the numbers together, and all the variables

6x-36x*()=0

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