(8x+2)/2=(9x-9)/3

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Solution for (8x+2)/2=(9x-9)/3 equation: 



(8x+2)/2=(9x-9)/3

We move all terms to the left:

(8x+2)/2-((9x-9)/3)=0

We calculate fractions


8x/()+(-((9x-9)*2)/()=0



We calculate terms in parentheses: +(-((9x-9)*2)/(), so:

-((9x-9)*2)/(

We multiply all the terms by the denominator


-((9x-9)*2)



We calculate terms in parentheses: -((9x-9)*2), so:

(9x-9)*2

We multiply parentheses

18x-18

Back to the equation:

-(18x-18)



We get rid of parentheses

-18x+18

Back to the equation:

+(-18x+18)



We get rid of parentheses

8x/()-18x+18=0

We multiply all the terms by the denominator


8x-18x*()+18*()=0

We add all the numbers together, and all the variables

8x-18x*()=0

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