(9x-4)/5=(8x+2)/10

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Solution for (9x-4)/5=(8x+2)/10 equation: 



(9x-4)/5=(8x+2)/10

We move all terms to the left:

(9x-4)/5-((8x+2)/10)=0

We calculate fractions


9x/()+(-((8x+2)*5)/()=0



We calculate terms in parentheses: +(-((8x+2)*5)/(), so:

-((8x+2)*5)/(

We multiply all the terms by the denominator


-((8x+2)*5)



We calculate terms in parentheses: -((8x+2)*5), so:

(8x+2)*5

We multiply parentheses

40x+10

Back to the equation:

-(40x+10)



We get rid of parentheses

-40x-10

Back to the equation:

+(-40x-10)



We get rid of parentheses

9x/()-40x-10=0

We multiply all the terms by the denominator


9x-40x*()-10*()=0

We add all the numbers together, and all the variables

9x-40x*()=0

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