(6x-20)+(3x+2)=180

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Solution for (6x-20)+(3x+2)=180 equation: 



(6x-20)+(3x+2)=180

We move all terms to the left:

(6x-20)+(3x+2)-(180)=0

We get rid of parentheses

6x+3x-20+2-180=0

We add all the numbers together, and all the variables

9x-198=0

We move all terms containing x to the left, all other terms to the right

9x=198

x=198/9

x=22

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