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(6x-1)(4x+6)=0
We multiply parentheses ..
(+24x^2+36x-4x-6)=0
We get rid of parentheses
24x^2+36x-4x-6=0
We add all the numbers together, and all the variables
24x^2+32x-6=0
a = 24; b = 32; c = -6;
Δ = b2-4ac
Δ = 322-4·24·(-6)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-40}{2*24}=\frac{-72}{48} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+40}{2*24}=\frac{8}{48} =1/6 $
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