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5x+2=(2x+3)/(x-1)
We move all terms to the left:
5x+2-((2x+3)/(x-1))=0
Domain of the equation: (x-1))!=0We multiply all the terms by the denominator
x∈R
5x*(x-1))-((2x+3)+2*(x-1))=0
We multiply parentheses
5x*(x-1))-((2x+3)+2x+=0
We add all the numbers together, and all the variables
2x+5x*(x-1))-((2x+3)=0
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