5(v-2)-7=-5(-2v+3)-v

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Solution for 5(v-2)-7=-5(-2v+3)-v equation: 



5(v-2)-7=-5(-2v+3)-v

We move all terms to the left:

5(v-2)-7-(-5(-2v+3)-v)=0

We multiply parentheses

5v-(-5(-2v+3)-v)-10-7=0



We calculate terms in parentheses: -(-5(-2v+3)-v), so:

-5(-2v+3)-v

We add all the numbers together, and all the variables

-1v-5(-2v+3)

We multiply parentheses

-1v+10v-15

We add all the numbers together, and all the variables

9v-15

Back to the equation:

-(9v-15)



We add all the numbers together, and all the variables

5v-(9v-15)-17=0

We get rid of parentheses

5v-9v+15-17=0

We add all the numbers together, and all the variables

-4v-2=0

We move all terms containing v to the left, all other terms to the right

-4v=2

v=2/-4

v=-1/2

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