(6x+5)/7=(2x+3)/15

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Solution for (6x+5)/7=(2x+3)/15 equation: 



(6x+5)/7=(2x+3)/15

We move all terms to the left:

(6x+5)/7-((2x+3)/15)=0

We calculate fractions


6x/()+(-((2x+3)*7)/()=0



We calculate terms in parentheses: +(-((2x+3)*7)/(), so:

-((2x+3)*7)/(

We multiply all the terms by the denominator


-((2x+3)*7)



We calculate terms in parentheses: -((2x+3)*7), so:

(2x+3)*7

We multiply parentheses

14x+21

Back to the equation:

-(14x+21)



We get rid of parentheses

-14x-21

Back to the equation:

+(-14x-21)



We get rid of parentheses

6x/()-14x-21=0

We multiply all the terms by the denominator


6x-14x*()-21*()=0

We add all the numbers together, and all the variables

6x-14x*()=0

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