(6x+22)+(64-x)=180

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Solution for (6x+22)+(64-x)=180 equation: 



(6x+22)+(64-x)=180

We move all terms to the left:

(6x+22)+(64-x)-(180)=0

We add all the numbers together, and all the variables

(6x+22)+(-1x+64)-180=0

We get rid of parentheses

6x-1x+22+64-180=0

We add all the numbers together, and all the variables

5x-94=0

We move all terms containing x to the left, all other terms to the right

5x=94

x=94/5

x=18+4/5

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