5x2-32x-64=0

Solution for 5x2-32x-64=0 equation:

5x^2-32x-64=0

a = 5; b = -32; c = -64;
Δ = b2-4ac
Δ = -322-4·5·(-64)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-48}{2*5}=\frac{-16}{10}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+48}{2*5}=\frac{80}{10}
=8
$